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Factorization

Introduction

Factorization is the process of breaking down an algebraic expression or a number into a product of simpler factors. It is a fundamental concept in algebra and is widely used in solving equations, simplifying expressions, and finding roots of polynomials.

Basic Concepts

  • Factor: A factor is a number or expression that divides another number or expression completely without leaving a remainder.
  • Prime Factorization: Breaking down a number into a product of prime numbers.
  • Factorization of Polynomials: Breaking down a polynomial into a product of simpler polynomials.

1. Common Factor Method

Example 1: Factorize 12xy2 18xy3

Solution:

GCF of 12 and 18 is 6, and common variables are x and y2.

12xy218xy3=6xy2(23y)

Example 2: Factorize 5a(x+y)+10b(x+y)

Solution:

=5(x+y)(a+2b)

2. Grouping Method

Example 1: Factorize x3+x2+x+1

Solution:

Group terms: (x3+x2)+(x+1)

Factor: x2(x + 1)+1(x + 1)=(x + 1)(x2+1)

Example 2: Factorize 2ab3ac+4bd6cd

Solution:

Regroup: (2ab3ac)+(4bd6cd)

Factor: a(2b3c)+2d(2b3c)=(2b3c)(a+2d)

3. Difference of Squares

Example 1: Factorize 25a249b2

Solution:

=(5a)2(7b)2=(5a7b)(5a+7b)

Example 2: Factorize x416

Solution:

=(x2)242=(x24)(x2+4)

Further factorize x24: (x 2)(x + 2)(x2+4).

4. Perfect Square Trinomials

Example 1: Factorize 4xy2 + 12xy + 9x

Solution:

Factor out x : x ( 4y2 + 12y + 9 )

Factor the trinomial: 4y2 + 12y + 9 = (2y+3) 2

Final result: x ( (2y+3) 2 ) .

Example 2: Factorize x2 10x + 25

Solution:

= (x5) 2

5. Quadratic Trinomials

Example 1: Factorize 2xy2 + 7xy + 3x

Solution:

Factor out x: x(2y2+7y+3)

Find factors of 2×3=6 that add to 7: 6 and 1.

Rewrite: 2y2 + 6y + y + 3

Factor: 2y ( y + 3 ) + 1 ( y + 3 ) = ( y + 3 ) ( 2y + 1 )

Final result: x ( y + 3 ) ( 2y + 1 )

Example 2: Factorize x2 3x 10

Solution:

Find two numbers that multiply to −10 and add to −3: −5 and 2.

Rewrite: x2 5x + 2x 10

Factor: x ( x 5 ) + 2 ( x 5 ) = ( x 5 ) ( x + 2 )

Mixed Problems

  1. Factorize 4xy2 9x

    Solution:

    Factor out x : x ( 4y2 9 )

    Apply difference of squares: x ( 2y 3 ) ( 2y + 3 )

  2. Factorize x3 8 (Difference of Cubes)

    Solution:

    Use formula: a3 b3 = ( a b ) ( a2 + ab + b2 )

    = ( x 2 ) ( x2 + 2x + 4 )

  3. Factorize a3 b3 (Difference of Cubes)

    Use formula: a3 b3 = ( a b ) ( a2 + ab + b2 )

    Example: m3 n3

    Solution: = ( m n ) ( m2 + mn + n2 )

Conclusion

Factorization is a crucial skill in algebra and is helpful in various fields of mathematics. The methods outlined here can be applied to many types of expressions and equations, making them easier to simplify or solve. Mastering these techniques provides a solid foundation for tackling more advanced algebraic problems.